Variational Calculus: When Is dg(r=r+) ≠ dg(r=r++)?

[PeteSampras]

Homework Statement

Question:

If $r_+ \neq r_{++}$ and $g(r=r_+) \neq g(r=r_{++})$

When is it fulfilled that $d g (r=r_+) \neq d g (r=r_+)$ ?

Homework Equations

$r_+ \neq r_{++}$
$g(r=r_+) \neq g(r=r_{++})$

The Attempt at a Solution

I tried computing $dg(r_+) = \frac{\partial g}{\partial r} \Big |_{r=r_+} dr_+$, but i am very confused. This is all the information that i have of this problem.

 

[WWGD]

Can you define #r_{+} , r_{++}## for us? Do it through a forehand or backhand, either is OK ;).

 

[PeteSampras]

Can you define #r_{+} , r_{++}## for us? Do it through a forehand or backhand, either is OK ;).

I don't understand your assumption. $r=r_+$ and $r=r_{++}$ are two differents points such that $r_{++}>r_+$

 

[WWGD]

I don't understand your assumption. $r=r_+$ and $r=r_{++}$ are two differents points such that $r_{++}>r_+$

Sorry, a tennis joke; guess you're tired of them ;).