Vector operations in polar coordinates?

AI Thread Summary
Vector operations can indeed be performed in polar coordinates, although they are more complex than in Cartesian coordinates. The discussion highlights the challenges associated with curvilinear coordinates, particularly in spherical systems. The provided links from MathWorld offer additional resources on vector derivatives and coordinate systems. Understanding these operations requires a grasp of the mathematical intricacies involved. Overall, while feasible, vector operations in polar coordinates demand careful consideration of the underlying principles.
Coeyo
Messages
2
Reaction score
0
Is it possible to do vector operations in polar coordinates?
 
Physics news on Phys.org
Coeyo said:
Is it possible to do vector operations in polar coordinates?

As you may probably have seen from the links provided,YES...Since we're talking about curvilinear coordinates,the calculations are more difficult than the ones with the old (\vec{i},\vec{j})

And for spherical it gets worse...

Daniel.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top