Velocity of mail bag released from helicopter

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    Helicopter Velocity
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The discussion focuses on calculating the velocity and height of a mail bag released from a helicopter ascending at 1.5 m/s. After 2 seconds, the final velocity of the mail bag is determined to be 21.1 m/s, accounting for gravitational acceleration of 9.8 m/s². The height of the mail bag after 2 seconds is calculated to be 57.8 meters. The calculations utilize the equation Vf = Vi + a*t effectively. The results illustrate the impact of gravity on the mail bag's motion after release.
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A small mail bag is released from a helicopter. The helicopter is rising with a constant speed of 1.5 m/s

After 2.0 seconds, what is the VELOCITY of the mailbag?
I use the equation Vf = Vi + a*t
and a would be 9.8 m/s squared right?
 
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yes 9.8 is correct

so what is the vel after 2 sec.

if the helicopter is at a height if 100 m what is the height of the bag after 2 secs
 
the velocity would be 21.1 m/s and the height of the bag would be 57.8 m ?
 
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