Velocity of Proton with 23.0 keV Kinetic Energy

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    Proton Velocity
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To calculate the speed of a proton with a kinetic energy of 23.0 keV, first convert the energy to joules, yielding 3.68e-15 J. The relevant equation for velocity is derived from kinetic energy, E_k = (1/2)mv^2. The mass of the proton is confirmed as 1.67e-27 kg. The kinetic energy value is used directly in the equation to solve for velocity. This approach effectively links energy and mass to determine the proton's speed.
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Homework Statement



What is the speed of a proton whose kinetic energy is 23.0 keV?

1 eV = 1.6e-19 J
23 Kev = 23000 eV = 3.68e-15 J

Homework Equations



V = Sq. Rt. ( - ((2)(q)(Vba)) / (m))

The Attempt at a Solution

 
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Just sub the values into the formula
 
What is each value? What is q, Vba, and M?

Is M = 1.67e-27 kg ?

And where does the KeV value go?
 
E_k=\frac{1}{2}mv^2

m=mass of a proton which you have. the eV is just another way to express energy.
 

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