Velocity vector and velocity intensity

AI Thread Summary
The discussion focuses on calculating the average velocity vector and velocity intensity from a given velocity vector in polar coordinates. The average velocity vector is determined using the integral of the velocity over a specified time period, while the velocity intensity is calculated using the formula for the magnitude of the velocity vector. A mistake in the calculation of the average velocity was identified, suggesting that the average acceleration does not require division by the time period. The correct approach emphasizes that the average acceleration can be directly derived from the initial and final velocities. The conversation highlights the importance of careful consideration in applying formulas correctly.
doktorwho
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Homework Statement


Given the velocity vector in the polar coordinates, ##\vec v=-awsin{wt}\vec e_r + awcos{wt}\vec e_\theta## determine the average velocity vector and velocity intensity over a time period ##[0, \pi/2w]##

Homework Equations


3. The Attempt at a Solution [/B]
For the first part where the average velocity vector is to be found i use
##\vec v_{avg}=\frac{\int_{0}^{\pi/2w}\vec vdt}{\pi/2w}##
and for the intensity part i use
##v=\sqrt{v^2_r+v^2_\theta}## first find the intensity which is just ##v=aw## and since the intensity is equal at all times i get for the second part
##\frac{2aw}{\pi/2w}## but i don't get correct results, where is my mistake?
 
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doktorwho said:
For the first part where the average velocity vector is to be found i use
##\vec v_{avg}=\frac{\int_{0}^{\pi/2w}\vec vdt}{\pi/2w}##
Which resulted in ...?
doktorwho said:
and for the intensity part i use
##v=\sqrt{v^2_r+v^2_\theta}## first find the intensity which is just ##v=aw## and since the intensity is equal at all times
right.
doktorwho said:
i get for the second part
##\frac{2aw}{\pi/2w}##
Think again about that step.
 
haruspex said:
Which resulted in ...?

right.

Think again about that step.
Well.. isn't average acceleration then just ##(v_i+v_f)/2##? Shouldnt i just get ##aw## then?
 
doktorwho said:
Well.. isn't average acceleration then just ##(v_i+v_f)/2##? Shouldnt i just get ##aw## then?
Yes. No need to divide by the period.
 
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