Vertical Load on a Purlin - find x and y force components

AI Thread Summary
To determine the force components on a roof purlin supporting a 300 lb vertical snow load, the perpendicular component is calculated using the formula 300 lb * cos(inverseTan(4/12)), while the parallel component is derived from 300 lb * sin(18.43°). The discussion emphasizes the importance of using a triangle to visualize the forces, where the hypotenuse represents the slope of the rafter. A free body diagram (FBD) may not be sufficient; understanding the geometry and trigonometry involved is crucial for accurate calculations. Properly analyzing the angles normal and tangential to the slope is essential for resolving the load components effectively.
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A roof purlin, supported by a roof rafter must support a 300 lb vertical snow load.
Determine the component of of the snow load as a concentrated load “P” both perpendicular and parallel to the axis of the rafter.

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I read that the perpendicular component of the 300lb force can be figured out by 300lb*cos(inverseTan(4/12)) and the parallel component can be figured out by 300lb*sin(18.43*)

I do not understand why this is so. My attempt at the solution is to draw an FBD, but I suppose I am drawing the wrong one.

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A free body diagram is nice, but what you really want to do is draw a triangle where the hypotenuse has a slope of 4:12 and then work out the angles normal and tangential to this slope. It's more a matter of geometry (and trigonometry) than anything else.
 
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