Very Simple Rotation Inertia of a Thin Rod Problem

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SUMMARY

The discussion focuses on calculating the rotational inertia of a meter stick (mass 0.68 kg) about an axis perpendicular to the stick at the 21 cm mark. The relevant equation for this calculation is I = ∫ r² dm, where 'I' represents the rotational inertia. The parallel axis theorem is recommended for finding the moment of inertia about the center of mass before applying it to the specified axis. This approach simplifies the calculation and enhances understanding of rotational dynamics.

PREREQUISITES
  • Understanding of rotational inertia concepts
  • Familiarity with the parallel axis theorem
  • Basic calculus for integration
  • Knowledge of mass distribution in rigid bodies
NEXT STEPS
  • Study the derivation of the moment of inertia for a thin rod
  • Learn how to apply the parallel axis theorem in various scenarios
  • Explore integration techniques for calculating rotational inertia
  • Investigate real-world applications of rotational dynamics in engineering
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to rotational inertia and the parallel axis theorem.

Oijl
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Homework Statement


Calculate the rotational inertia of a meter stick, with mass 0.68 kg, about an axis perpendicular to the stick and located at the 21 cm mark. (Treat the stick as a thin rod.)


Homework Equations


I = integral of radius squared with respect to mass


The Attempt at a Solution


I'm not quite sure how to explain my issue here, but I think all I need is to see this worked out, and then I could probably understand the nature of these problems. Thanks.
 
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You could use the parallel axis theoram if you know how to find the M.I about the centre of mass of the rod (the centre) :smile:
 

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