Vibration Problem: Determine Period

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To determine the period of vibration for a uniform rod attached to a spring, the spring constant (k = 820 N/m) and the mass of the rod (6 kg) are essential. The initial displacement of the rod (10 mm) creates a spring force of 8.2 N, while the weight of the rod is calculated as 58.86 N. The discussion emphasizes using energy methods, specifically conservation of energy, to derive the equation of motion, which will lead to the natural frequency and subsequently the period. The need to consider torque and moment of inertia due to the restraint at point C is also highlighted. Ultimately, the period can be calculated from the natural frequency obtained through these methods.
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Homework Statement


The uniform rod shown has mass 6 kg and is attached to a spring of constant k = 820 N/m. End B of the rod is depressed 10 mm and released.

Determine the period of vibration.

Picture is attached below

Homework Equations


Fs = kx
W = mg

The Attempt at a Solution


I honestly don't quite know how to even start a problem like this.
Fs = (820 N/m)(0.010 m) = 8.2 N
W = (6 kg)(9.81 N/kg) = 58.86 N
The spring force will act on the right end of the bar and the weight will act in the middle (@400 mm).

How am I supposed to proceed on this type of question? Do I need the torque about C?
 

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You may assume the situation shown is the equilibrium position.
Clearly there is a restoring force trying to go back to equilibrium and there is some inertia in going there.
The restraint at point C makes that indeed you need to consider torque and moment of inertia, so you are on the right track. Proceed !
 
The easiest approach is to use energy methods, based on kinetic and potential energies.
 
Dr.D said:
The easiest approach is to use energy methods, based on kinetic and potential energies.
How would that be done?
Initially the energy in the system would be the spring energy and perhaps relative gravitational energy. However, how would that be related to period?
 
Use conservation of energy to determine the equation of motion. The natural frequency falls out of the equation of motion, and the period is calculated from the natural frequency.
 
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