Voltage drop across a resistor in a circuit

Click For Summary

Homework Help Overview

The discussion revolves around determining the voltage drop across a specific resistor in a circuit involving three batteries and four resistors connected in a loop. The original poster has previously calculated the current in the loop and the voltage across certain points.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster considers using Ohm's Law to find the voltage drop and questions whether additional steps are necessary after calculating the product of current and resistance.

Discussion Status

Participants have provided guidance on using loop laws and Ohm's Law to find the voltage drop. The original poster expresses some uncertainty about the simplicity of the approach, but others affirm that the method is correct.

Contextual Notes

The original poster is working through a multi-part problem and is focused on the specific calculation for one resistor within the broader circuit context.

pcml100
Messages
23
Reaction score
0

Homework Statement



Three batteries and four resistors are connected in a loop as shown (see attachment).

What is the voltage drop across the top left resistor?

Homework Equations



V = IR

The Attempt at a Solution



This is part 3 of the 3 questions for this problem. On the other two I found the current of the loop and the voltage across points a and b.

I think that all I need to do here is multiply IR (R being the value of that resistor) but that just seems too easy. Do I have to subtract it from the total voltage for the circuit or something?
 

Attachments

  • circuit.jpg
    circuit.jpg
    5.5 KB · Views: 473
Physics news on Phys.org
All you need to do is use loop laws to find the current, and then you can find the voltage drop over the resistor using Ohm's law.
 
Ok. I already found the current in the circuit and I assumed that I needed to use Ohm's Law to find the voltage drop, but my question is whether I just multiply the current in the loop by the value for the specific resistor and that's it, or if I have to do something after that step?
 
That's it.
 
Awesome. Just seemed too easy so I thought maybe something else was going on. Thank you
 

Similar threads

Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
9
Views
1K
Replies
14
Views
2K
Replies
9
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K