Voltage in a Circuit: Calculate with Current Divider

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The discussion focuses on calculating voltage in a circuit using the current divider method. The initial approach involves finding the equivalent resistance of the circuit, which is expressed as R1R2/(2R1 + 2R2). The user struggles with the calculations and seeks clarification on the relationship between voltage (Vo) and current (Is), emphasizing that Vo does not depend on branch current. The conversation highlights the importance of converting equivalent resistance into conductance (G) to derive the correct answer. Ultimately, the discussion aims to clarify the correct method for calculating Vo across the desired branch.
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Homework Statement



http://img696.imageshack.us/img696/7609/circuit.jpg

Homework Equations





The Attempt at a Solution



I know that the answer of the question below is D, but how do I get to that answer?

My guess would be to use current divider to find the current going through v0 then we can calculate v0 then divide by is.

When I do that I got a very complicated result...

My calculations for the current divider is to find the equivalent resistance in the circuit, which is:

R1R2/R1+R2 || R1R2/R1+R2
which is R1R2/2R1+2R2

Then after calculating the v0/is I got R1R2/2(R1+R2). This doesn't seem to match the answers above
is this approach correct so far?
 
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Vo/Is is the resistance. It does not depend on the branch current. The current in the circuit is Is. Vo is the same for R1 and R2.
So what is Vo across that branch? Convert the equivalent resistance into G to get the required answer.
 
rl.bhat said:
Vo/Is is the resistance. It does not depend on the branch current. The current in the circuit is Is. Vo is the same for R1 and R2.
So what is Vo across that branch? Convert the equivalent resistance into G to get the required answer.

the equivalent resistance is this:

R1R2/2R1+2R2
 
-EquinoX- said:
the equivalent resistance is this:

R1R2/2R1+2R2
From where did you get 2?
The resistance of desired branch is \frac{1}{G_{}1+G_{}2}
 
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