Volume expansion problem wheres initial volume?

AI Thread Summary
The discussion centers on calculating the coefficient of volume expansion (beta) for a liquid with given densities at two temperatures. The user initially assumes an initial volume of 1 cm³ for their calculations but realizes this may be incorrect. They calculate beta as 0.00115325, but the system indicates this is wrong. Participants suggest verifying the problem's details and checking the density values provided. The conversation highlights the importance of accuracy in problem interpretation and calculation methods.
Dantes
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A liquid has a maximum density of 0.6 g/cm^3 at 3.7 C. At 11.4C , its density is 0.60888 g/cm^3. What is beta for this liquid over this temperature interval? Answer in units of (C)^-1.

Obviously this has to do with the volume expansion so I made the formula deltaV = beta * initial volume * delta temperature into beta = deltaV / (initial volume * delta temperature) assuming that initial volume is 1 cm since its not stated in the problem and that's wrong.

I came out with 0.00115325 doing it that way. System says I am wrong.

Am I on the right track or am I not thinking outside the box enough?
 
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Hmm...switching to kelvin opps :biggrin:

edit: doesn't matter since its a constant.
 
Dantes said:
A liquid has a maximum density of 0.6 g/cm^3 at 3.7 C. At 11.4C , its density is 0.60888 g/cm^3. What is beta for this liquid over this temperature interval? Answer in units of (C)^-1.
Obviously this has to do with the volume expansion so I made the formula deltaV = beta * initial volume * delta temperature into beta = deltaV / (initial volume * delta temperature) assuming that initial volume is 1 cm since its not stated in the problem and that's wrong.
I came out with 0.00115325 doing it that way. System says I am wrong.
Am I on the right track or am I not thinking outside the box enough?

Is 0.60888 less than, equal to, or greater than 0.6? Methinks you need to check the question, and if you've copied it correctly, it's time to pick bones with whoever programs the exercises into the "system."
 
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