Volume flow rate through air ducts

AI Thread Summary
To calculate the volume flow rate through the ducts, the area of each duct must first be determined. The cross-sectional area of the two 8"x10" ducts is 80 in² each, leading to a combined flow rate of 2400 ft³/s when multiplied by the average speed of 30 ft/s. The area of the 18"x14" duct is 252 in², which allows for the calculation of the average speed in this section using the conservation of mass principle. By equating the total flow rates, the average speed in the 18"x14" duct can be derived. This approach provides a clear method to solve the problem based on the given dimensions and velocities.
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Homework Statement


Air flows through two 8"x10" ducts that merge into a single 18"x14" duct. (Ducts are in 3D)
The average speed of air in each of the 8"x10" ducts is 30 ft/s.
What is the volume flow rate, of air in the 18"x14" section of the duct? Express the volume flow rate in ft^3/s
What is the average speed of air in the 18"x14" duct?

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The Attempt at a Solution


I really don't know where to start on this one :frown:
 
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Given the dimensions of the ducts and the velocity of the flow thru them, how would you calculate the volumetric flow rate in each of the ducts? Read the problem carefully and look at the diagram.
 
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