Volumetric Analysis Lab Calculation Question

  • Thread starter supahman
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  • #1
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Homework Statement



Hi there, I am asked this question in one of my lab calculation questions:

Calculate the number of moles of I2 produced from 25 mL of the diluted KIO3 solution.

Information that has already been obtained from my lab:

-Molar concentration of dilute KIO3: 0.00241 + or - .5% M
-Molar concentration of stock KIO3 solution : 0.0241 + or -0.05%

-Mass of I2: 253.8 g/mol
-Mass of KIO3:



Homework Equations



-Avogadro's Constant: 6.02214 X 10^23

The Attempt at a Solution



-Was not able to properly attempt the questions, as I am unsure where to being and how to complete it.
 
Last edited:

Answers and Replies

  • #2
symbolipoint
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Your question should be, find how much I2 is produced from the given quantity of KIO3. This is assuming that the KIO3 is the source of the produced I2.

Your part of the reaction would include: KIO3 → (1/2) I2

You have enough information for how much moles of KIO3, and you know that half a mole of I2 comes from one mole of KIO3.

By any chance, does the situation have additional important information which you did not include?
 
  • #3
Borek
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This is assuming that the KIO3 is the source of the produced I2.
Which is probably not a correct assumption.

(I guess that's what you hinted at in your last statement.)
 
  • #4
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Hey there,

That was all the information I was given. The I2 is what is used to produce the stock KIO3, which is then diluted with filtered water.
 
  • #6
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Huh? I'm actually asked that question... So I really don't know what to make of it. :s
 
  • #7
Borek
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Perhaps you are expected to know what the standard procedure is. Potassium iodate is a primary substance, and the way it is used is well known.
 

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