Water Flow Rate From A Tap Attached 2 A Tank

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Discussion Overview

The discussion revolves around calculating the flow rate of water from a tap attached to a 400-liter cylindrical tank. Participants explore the application of Bernoulli's equation and the continuity equation to determine flow rate and the distance the water may travel.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant asks how to calculate the flow rate and the distance water might travel from a tap at the bottom of a cylindrical tank.
  • Another participant suggests using Bernoulli's equation and the continuity equation to find the flow rate, providing a formula involving velocity, pressure, height, and cross-sectional area.
  • Further clarification is requested regarding the variables in the equation, specifically the meanings of g (gravity), h (height), P1 (pressure at the top), P2 (pressure at the bottom), A1 (area of the tank), A2 (area of the outlet), and ρ (density of the fluid).

Areas of Agreement / Disagreement

Participants have not reached a consensus on the calculations, as some seek further clarification on the variables and equations involved, indicating uncertainty in understanding the application of the equations presented.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the application of Bernoulli's equation, such as whether the tank is open to the atmosphere and how that affects the pressures involved.

TIPSY
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Hi guys. Can u pls hlp me out.

Let's say I have a 400 liter cylindrical tank with a tap at the botom.

how do I calculate the rate at which the water flows from the tap and how far the water mite go?

thanx in advance
 
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TIPSY said:
Hi guys. Can u pls hlp me out.

Let's say I have a 400 liter cylindrical tank with a tap at the botom.

how do I calculate the rate at which the water flows from the tap and how far the water mite go?

thanx in advance

The flow rate at the outlet can be found using Bernoulli's equation along with the continuity equation.

[tex]v_2 = \sqrt{{\frac{2}{1- \left( \frac{A_2}{A_1}\right)^2}} \cdot \left(\frac{P_1 - P_2}{\rho} + g \cdot h \right)[/tex]

CS

EDIT: I forgot to mention that you need to multiply v2 by the cross-sectional area to get the flow rate (v2 is just the velocity).
 
Last edited:
OK. I think I know what g and h are (gravity and height) but the rest I am clueless so ifyou could just explain further it would be appreciated.

thanks stewartcs.
 
TIPSY said:
OK. I think I know what g and h are (gravity and height) but the rest I am clueless so ifyou could just explain further it would be appreciated.

thanks stewartcs.

P1 is the pressure at the top of the tank.
P2 is the pressure at the bottom of the tank.

If the tank is open to atmosphere and discharges to atmosphere the equation will obviously reduce. If not, use P1 and P2 as applicable.

h is the height from the top of the fluid in the tank to the centerline of the orifice.

A1 is the area of the tank.
A2 is the area of the orifice (outlet).

g is gravitational acceleration.

[tex]\rho[/tex] is the fluid's density.

CS
 

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