What Angles Should a Fire Hose Nozzle Point to Land Water 2.0m Away?

AI Thread Summary
To determine the angle at which a fire hose nozzle should point to land water 2.0 meters away, the discussion emphasizes using projectile motion equations. The water is ejected at a speed of 7.8 m/s, and participants suggest applying the range equation to find the optimal angle. Key variables include the initial velocity, horizontal distance, and gravitational acceleration. The equation Vo^2/9.80 * sin(θ) = r can be utilized to solve for the angle (θ). Understanding these components is crucial for accurately calculating the desired angle for effective water projection.
Sn0wPr0
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A fire hose held near the ground shoots water at a speed of 7.8 m/s.

At what angles should the nozzle point in order that the water land 2.0 m away



I don't even know where to start. Can anyone set me in the right direction?
 
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Forget about the fact that it's a stream of water and think about normal projectiles.
 
i just can't figure out how to find the component vectors, which is where i think i need to start.
 
Sn0wPr0 said:
A fire hose held near the ground shoots water at a speed of 7.8 m/s.

At what angles should the nozzle point in order that the water land 2.0 m away



I don't even know where to start. Can anyone set me in the right direction?

Do you know the equations for projectile motion?
 
yea, i have them in front of me but I'm having trouble applying them right now.

i'm so frustrated right now i just don't know where to start.
 
i'm starting to think it has something to do with the range equation. am i going in the right direction?

do i set it equal for sin?

(Vo^2/9.80)sin0=r
 
You know your speed, and you know your dX (horizontal distance) and you obviously know g. So use the equation with these variables and solve for the angle (theta).
 
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