What are the forces and angles involved in dragging a sled with ropes?

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To drag the sled with a coach at a steady speed of 1.80, the players must exert a force that matches the friction force of 1220. The angle between the ropes is 15 degrees, which means the pulling force is not entirely effective in overcoming friction. A vector diagram should be sketched to visualize the forces, with the effective force calculated using trigonometry, specifically F*cos(15) or F*sin(15). The total force exerted by both players must equal the friction force, allowing for the calculation of the required pulling force per player. Accurate unit usage is essential for clarity in the calculations.
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Homework Statement



A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1220 and the angle between the two ropes is 15.0. How hard must each player pull to drag the coach at a steady 1.80 ?


Homework Equations



Not sure on what equations to use.

The Attempt at a Solution



Haven't really attempted it cause I don't know how to start it. If someone could just give me the equations to use, I think I could get it.

Thanks
 
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The pullers must match the force of friction. Their pulling force is partly wasted because they are not pulling straight ahead. You must sketch a vector at 15 degrees away from straight ahead, sketch in the rest of the right triangle of which the vector is the hypotenuse. Then use trigonometry to find the part of the F that is straight ahead. It will be F*cos(15) or F*sin(15). Finally, twice that will be equal to the friction force and you can then solve for F.
 
Please use units when posting quantities. They are meaningless without them.
 
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