What Are the Key Thermodynamics Concepts in These Questions?

AI Thread Summary
As temperature approaches zero, the value of (∂U/∂V)_T tends to zero, as both thermal expansivity and heat capacity approach zero. For the heat pump, the minimum power consumption can be calculated using the Carnot efficiency formula, which relates the heat delivered and the work input based on the temperatures of the reservoirs. The discussion on measuring Cv to determine entropy differences emphasizes the relationship between heat transfer and entropy change, particularly under constant volume conditions. The integration of temperature with respect to entropy provides a way to quantify these changes. Overall, the thread addresses key thermodynamic principles relevant to the posed homework questions.
CAF123
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Homework Statement


a)What value does ##\left(\frac{\partial U}{\partial V}\right)_T## tend to as T tends to 0?

b)A heat pump delivers 2.9kW of heat to a building maintained at 17oC extracting heat from the sea at 7oC. What is the minimum power consumption of the pump?

c)Explain how a measurement of ##C_v## can be used to determine the difference in entropy between equal volume equilibrium states at different temperatures.

Homework Equations


Cyclic rule, Carnot efficiencies, third law of thermodynamics

The Attempt at a Solution



a)I used the cyclic rule here and wrote $$\left(\frac{\partial U}{\partial V}\right)_T \left(\frac{\partial V}{\partial T}\right)_U \left(\frac{\partial T}{\partial U}\right)_V = -1$$ to give $$\left(\frac{\partial U}{\partial V}\right)_T = -\frac{C_v}{V \beta_U}$$ where ##C_v## is the constant volume heat capacity and ##\beta_U## is the thermal expansivity at constant U. I think both the thermal expansivity and heat capacity both tend to 0 as T goes to 0, so overall the quantity of interest goes to 0 too. Is this okay?

b) I am a bit confused of the set up (see attached for what I think is going on). Generally for a heat pump the efficiency is defined as Q1/W, where Q1 is the heat supplied to some region and W is the work you had to do to supply the heat. If the heat pump operates between two reservoirs, then max efficiency is T1/(T1-T2), where T2 is the lower temperature reservoir (the sea in this case).

c) ##Q = \int T dS \Rightarrow## $$\left(\frac{\partial Q}{\partial T}\right)_V \equiv C_v = \frac{\partial}{\partial T} \int T dS = \int dS + \int T \left(\frac{\partial S}{\partial T}\right)_V$$ Is this helpful?

Many thanks.
 

Attachments

  • Heat pump.png
    Heat pump.png
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For part c, if the heat is added reversibly at constant volume,

dqrev=CvdT

dS = dqrev/T

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