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Hi all,
I got a 3 part Qs: γ=1/√1-v^2-c^2
Part A
Consider the Lorentz transformation tensor
Matrix
Row 1: [ γ 0 0 -vγ/c]
Row 2: [ 0 1 0 0 ]
Row 3: [ 0 0 1 0 ]
Row 4:-[vγ/c 0 0 γ ]
for transforming 4-vectors from frame S to \overline{S} according to\overline{A}^{\mu} = L^{\mu} _{v} A^{v} . The coordinate system is x^{0} =ct, x^{1} = x, x^{2} = y, x^{3} = z .
Doing the transformation and then solving for it gives the answer:
d/d\overline{t}=γ(d/dt-vd/dx), d/d\overline{x}=γ(v/c^2 d/dt - d/dx), d/d\overline{y} = d/dy, d/d\overline{z}=d/dz
That's the answer I get but I am not sure about if I have the addition and substraction signs correct.
Part B
In above question, if the 4-vector potential is given by \underline{A}=(\phi/c, Ax, Ay, Az) in frame S what are its components in frame \overline{S}?
Again solving for and getting the answer, I am confused on the addition and subtraction signs:
\overline{A}=(γ\varphi/c + γv/c Ax, γAx+ γv\varphi/c^2, Ay, Az)
Part C
In Part B, the electric and magnetic fields are defined in frames S and \overline{S} by
E^{(3)}=-∇\varphi-dA^{(3)}/dt, \overline{E}^{(3)}=-∇\overline{\varphi}-d\overline{A}^{(3)}/d\overline{t}, B^{(3)}=∇xA^{3}, \overline{B}^{(3)}=\overline{∇}x\overline{A}^{(3)},
\overline{A}=(\overline{\varphi}/c, \overline{A}x,
If
\overline{A}y, \overline{A}z)=(\overline{\varphi}/c, \overline{A}^{(3)})
what is value of \overline{E}x?
Again solving for it I get my answer in which I am unsure of the addition and subtraction signs.
\overline{E}x=Ex, \overline{E}y=γ(Ey+vBz), \overline{E}z=γ(Ez-vBy)
I am also not sure if the have the vector components assigned to the correct axis.
Help would be appreciated.
I got a 3 part Qs: γ=1/√1-v^2-c^2
Part A
Homework Statement
Consider the Lorentz transformation tensor
Matrix
Row 1: [ γ 0 0 -vγ/c]
Row 2: [ 0 1 0 0 ]
Row 3: [ 0 0 1 0 ]
Row 4:-[vγ/c 0 0 γ ]
for transforming 4-vectors from frame S to \overline{S} according to\overline{A}^{\mu} = L^{\mu} _{v} A^{v} . The coordinate system is x^{0} =ct, x^{1} = x, x^{2} = y, x^{3} = z .
The Attempt at a Solution
Doing the transformation and then solving for it gives the answer:
d/d\overline{t}=γ(d/dt-vd/dx), d/d\overline{x}=γ(v/c^2 d/dt - d/dx), d/d\overline{y} = d/dy, d/d\overline{z}=d/dz
That's the answer I get but I am not sure about if I have the addition and substraction signs correct.
Part B
Homework Statement
In above question, if the 4-vector potential is given by \underline{A}=(\phi/c, Ax, Ay, Az) in frame S what are its components in frame \overline{S}?
The Attempt at a Solution
Again solving for and getting the answer, I am confused on the addition and subtraction signs:
\overline{A}=(γ\varphi/c + γv/c Ax, γAx+ γv\varphi/c^2, Ay, Az)
Part C
Homework Statement
In Part B, the electric and magnetic fields are defined in frames S and \overline{S} by
E^{(3)}=-∇\varphi-dA^{(3)}/dt, \overline{E}^{(3)}=-∇\overline{\varphi}-d\overline{A}^{(3)}/d\overline{t}, B^{(3)}=∇xA^{3}, \overline{B}^{(3)}=\overline{∇}x\overline{A}^{(3)},
\overline{A}=(\overline{\varphi}/c, \overline{A}x,
If
\overline{A}y, \overline{A}z)=(\overline{\varphi}/c, \overline{A}^{(3)})
what is value of \overline{E}x?
The Attempt at a Solution
Again solving for it I get my answer in which I am unsure of the addition and subtraction signs.
\overline{E}x=Ex, \overline{E}y=γ(Ey+vBz), \overline{E}z=γ(Ez-vBy)
I am also not sure if the have the vector components assigned to the correct axis.
Help would be appreciated.