What are the properties of these three functions?

[azatkgz]

Among the following function,
-one is continuous everywhere,but not differentiable at 0
-one is differentiable,but derivative is discontinuous at 0
-one is differentiable and has continuous derivative

1)f(x) = \left\{\begin{array}{cc}\ln (1 + x^3)\sin\frac {1}{x},x &gt; 0 \\<br /> 0,x\leq0\end{array}\right

2)g(x) = \left\{\begin{array}{cc}\ln^2(1 + x)\sin\frac {1}{x},x &gt; 0 \\<br /> 0,x\leq0\end{array}\right

3)h(x) = \left\{\begin{array}{cc}\ln (1 + \frac {\sin x}{2}),x &gt; 0 \\<br /> x\leq0\end{array}\right

Solution:

1)\lim_{x\rightarrow 0}\frac {\ln (1 + x^3)\sin\frac {1}{x}}{x} = \lim_{x\rightarrow 0}\frac {(x^3 + 0{x^6})\sin\frac {1}{x}}{x} = 0

differentiable

f&#039;(x) = \frac {3x^2\sin\frac {1}{x}}{1 + x^3} - \frac {\cos\frac {1}{x}\ln (1 + x^3)}{x^2}

2)\lim_{x\rightarrow 0}\frac {(x^2 + o(x^4))\sin\frac {1}{x}}{x} = 0 differentiable

g&#039;(x) = \frac {2\ln (1 + x)\sin\frac {1}{x}}{1 + x} - \frac {\cos\frac {1}{x}\ln^2 (1 + x)}{x^2}

3)\lim_{x\rightarrow 0}\frac {(\frac {\sin x}{2} + 0(\sin^2x))\sin\frac {1}{x}}{x} = \lim_{x\rightarrow 0}\sin\frac {1}{x} not differentiable

I couldn't find which function f'(x) or g'(x) is not differentiable at 0,which one continuous.

 

[Gib Z]

This may not be the most analytical method, but try graphing these functions, it becomes easier to see.