What Are the Velocities of the Broken Parts in a Plane Explosion?

AI Thread Summary
The discussion revolves around calculating the velocities of two parts of a plane that exploded, using conservation of momentum principles. A 5000 kg plane moving at 150 m/s breaks into a 2000 kg part and a 3000 kg part, with the larger part moving at 400 m/s in the opposite direction post-explosion. The user attempts to apply momentum conservation but struggles to arrive at the correct velocities, which are stated to be 310 m/s and 90 m/s. The calculations involve setting up equations based on initial and final momentum, but the user expresses confusion about their approach and seeks clarification. Ultimately, the discussion highlights the challenges of applying physics concepts to solve real-world problems.
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Homework Statement


A plane of a mass 5000 kg moving horizontally in 150 m/s break into two parts 2000 kg and 3000 kg because of a internal explosion. If the bigger part be thrown away with a 400 m/s relative to other part to opposite direction of previous moved direction before explosion, find the velocity of each part. [Ignore the air resistance]


Homework Equations


Conservation of momentum
E=mv2/2


The Attempt at a Solution



I tried this, but I failed to do this one.

I don't know this is right or wrong
According to conservation of momentum

5000 x 150 - 3000u = 5000 x (400 - 150) - 400 x 3000
3(400 - u) = 50
1200 -3u = 50
1150 = 3u
u = 383.6

color black = Initial momentum of whole plane,
color blue = Initial momentum of 3000 kg part
color lime = final momentum of 3000 kg part
color red = final velocity of whole plane

The part in red or final velocity of whole plane. Is it right to take like that. I multiplied mass by the difference of initial velocity of plane and final velocity of 3000 kg part.

Please help me to do this
 
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According to the answer script, the two velocities are 310 m/s and 90 m/s. My all tries are went wrong. I could not reach to this.
 
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