What Beat Frequency Results from Unequal Tensions in Piano Strings?

AI Thread Summary
The discussion focuses on calculating the beat frequency produced by two piano strings tuned to the same note but under different tensions. The equation for beat frequency, f(beat) = f1 - f2, is confirmed as appropriate for this problem. To find the second frequency, the relationship between string tension and frequency is essential, which can be derived from the equation Tension = (velocity^2) * (mass/length). Although specific values for mass and length are not provided, they are not necessary since they remain constant. The key is to determine how the change in tension affects the frequency, allowing for the calculation of the beat frequency in beats per second.
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Homework Statement


In certain ranges of a piano keyboard, more
than one string is tuned to the same note to
provide greater intensity. For example, the
note at 162 Hz has two strings at this pitch.
If one string slips from its normal tension of
645 N to 516 N, what beat frequency will be
heard when the two strings are struck simul-
taneously? Answer in units of beats/s.


Homework Equations


f(beat)=f1-f2


The Attempt at a Solution



Am i using the right equation?
 
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I think so...also you will need the relationship between the tension in the string and the frequency of vibration
 
how would I do that because
the question is asking me beats per sec
how would i get ther relationship between the tension and the frequency
 
That equation is indeed helpful for solving this problem. You'll need to figure out the second frequency however.
 
physics10189 said:
how would I do that because
the question is asking me beats per sec
how would i get ther relationship between the tension and the frequency
What equation does your textbook have that involves the string tension?
 
Tension=(velocity^2)*((mass)/(length))

which i have neither of the length of the string nor the mass of it.
 
That's okay, since the mass and length do not change for the string they are not needed.

You can use that equation to figure out by what factor the velocity (and therefore the frequency) changes when the tension changes by a factor of 516/645
 
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