What do the symbols in the equation for a damped harmonic oscillator represent?

  • Thread starter Thread starter JolleJ
  • Start date Start date
  • Tags Tags
    Damped Oscillator
AI Thread Summary
The discussion focuses on the symbols in the equation for an underdamped harmonic oscillator, specifically A*e^{k*t}*sin(w*t). A represents the amplitude, while k is identified as the damping constant. The symbol w is clarified as angular frequency, which describes the oscillation's phase evolution, with one cycle corresponding to w*t reaching 2π. Participants also discuss the period of the movement, noting that it is T=2π/w and that the period for a damped oscillator is indeed longer than that of an undamped one, although it remains constant. The conversation emphasizes the importance of understanding these concepts in physics.
JolleJ
Messages
34
Reaction score
0
Hi there.

I'm having a problem explaining the physical meaning of the symbols in the equation for an underdamped Harmonic oscillator:

A*e^{k*t}*sin(w*t)

I can see that A is the amplitude of the first swing, which we will not see, since sin(w*t)=0 for t=0.
Now k is the damping constant and something, I don't what more to say about that.

The last one, w, I find the hard one. I cannot tell, what this is. I mean, it's not the angular velocity, since this is changing. It is some sort of frequency?

Likewise, when the oscillator is not damped, and the equation is:

A*sin(w*t)

What is the w here? Is the actual angualar speed here?
//EDIT:
Wait, I see that it cannot be angular speed here either, since this is of course also constantly changing, both in size and direction. I can't see, what it is. If someone could please exemplify it? Thanks. :)
//

Thanks in advance.
 
Physics news on Phys.org
It is an angular frequency (not velocity), describing the evolution of the phase of the oscillation... when w*t goes through 2pi the oscillation has gone through one cycle.
One cycle is one rotation in complex displacement space if we use the identity sin[wt]=Im[exp[i*w*t]]
 
Thank you both very much!
However, I'm still having one problem. What is the period of the movement? I've heard that it's larger than for an undamped pendulum. Is this true? And also, is the period constant for a damped pendulum? I can't tell this from the equations, but some of you can maybe?

Thanks in advance.
 
What class is this for, physics I probably?

The period is T=2*pi/w [Hz]

Its the number of cycles each second of the body.

Your book should explain these things very clearly.

Keep asking questions and the math to your answers are going to get damn horrible real quick!
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top