What Does the Improper Integral \int^{\infty}_{o}\frac{sinx}{x} Mean?

twalker40
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1. Let F(x)= \int^{x}_{0} \frac{sint}{t} and f(x) = \frac{sinx}{x}. If x approaches infinity, F(x) approaches \pi/2. So, Explain what does this mean for the improper integral \int^{\infty}_{o}\frac{sinx}{x}



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Explain what does this mean for the improper integral \int^{\infty}_{o}\frac{sinx}{x}


The Attempt at a Solution

 
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What is the definition of
\int_a^\infty f(x) dx[/itex]?
 
So I am guessing that \int^{\infty}_{o}\frac{sinx}{x} converges to pi/2?. The question seems straight forward but my teacher isn't that forgiving, I am thknking there's more to it?
 
Is there any reason why you called the integrand function f? You never used that definiiton in the sequel. Are you sure you copied the question correctly? As it stands it really looks somewhat like senseless:smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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