What Does the Improper Integral \int^{\infty}_{o}\frac{sinx}{x} Mean?

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Homework Help Overview

The discussion revolves around the improper integral \(\int^{\infty}_{0}\frac{\sin x}{x} \, dx\) and its interpretation, particularly in relation to the function \(F(x) = \int^{x}_{0} \frac{\sin t}{t} \, dt\) and its limit as \(x\) approaches infinity.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the meaning of the improper integral and its convergence, with one participant questioning the definition of the integral and another expressing uncertainty about the implications of the limit approaching \(\pi/2\).

Discussion Status

The discussion is ongoing, with participants raising questions about definitions and the reasoning behind the convergence of the integral. There is no explicit consensus yet, and some participants are probing deeper into the assumptions and interpretations of the problem.

Contextual Notes

One participant notes concerns about the clarity of the definitions used in the problem, suggesting that there may be misunderstandings or miscommunications regarding the setup.

twalker40
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1. Let F(x)= \int^{x}_{0} \frac{sint}{t} and f(x) = \frac{sinx}{x}. If x approaches infinity, F(x) approaches \pi/2. So, Explain what does this mean for the improper integral \int^{\infty}_{o}\frac{sinx}{x}



Homework Equations


Explain what does this mean for the improper integral \int^{\infty}_{o}\frac{sinx}{x}


The Attempt at a Solution

 
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What is the definition of
\int_a^\infty f(x) dx[/itex]?
 
So I am guessing that \int^{\infty}_{o}\frac{sinx}{x} converges to pi/2?. The question seems straight forward but my teacher isn't that forgiving, I am thknking there's more to it?
 
Is there any reason why you called the integrand function f? You never used that definiiton in the sequel. Are you sure you copied the question correctly? As it stands it really looks somewhat like senseless:smile:
 

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