What Forces Act on a Static Cylinder on an Inclined Plane?

AI Thread Summary
A static cylinder on an inclined rough plane experiences three main forces: weight, reaction force, and tension. The weight component acting down the slope must equal the sum of friction and tension for equilibrium. Friction opposes both translational motion down the incline and the torque caused by tension. A proper force diagram is essential for visualizing these interactions and confirming that all forces must act through a common point. Understanding these dynamics is crucial for analyzing the stability of the cylinder on the incline.
devious b
Messages
4
Reaction score
0
Hi everyone,

If I have a static cylinder on an inclined rough plane at an angle alpha supported by a chord under tension, which leaves the surface of the cylinder at a tangent upwards and parallel to the plane. Does the weight component trying to pull it downwards equal the sum of the friction + tension? And does the friction oppose the translational motion, rotational, or both?
:confused:

Any insights are appreciated, thx.
 
Last edited:
Physics news on Phys.org
Draw a force diagram. If the cylinder is not rotating what can you say about the forces/torques?
 
  • Like
Likes 1 person
hi devious b! :smile:

there's only three forces: the weight, the reaction force, and the tension

so they must all go through the same point :wink:

(because … ?)
 
  • Like
Likes 1 person
My problem is the force diagram. Does the friction F act upward opposing the motion down and the torque caused by the tension?
 
if you follow my hint, it'll automatically give you the answer to that :smile:
 
Back
Top