What Happens When Multiple Slits Are Used for Diffraction?

AI Thread Summary
The discussion explores the implications of using multiple slits in diffraction experiments, building on the established Fraunhofer diffraction formula for a single slit. It raises questions about the resulting patterns when transitioning from a single slit to double or multiple slits, as well as the effects of introducing an obstacle that allows light to pass around it. The user seeks clarification on how these changes affect the diffraction patterns observed on a screen. The conversation indicates an interest in understanding the mathematical and physical principles governing these phenomena. Overall, the inquiry highlights the complexity of diffraction as the number of slits increases and the role of obstacles in light behavior.
carlosbgois
Messages
66
Reaction score
0
Hi there. It's not actually a problem, I was just trying to figure it out, so idk if this is the right section for this post, but anyways: I've managed to derive the expression for the Fraunhofer diffraction in a single slit, such that the distance between a minimum and the central point is given (in an approximation) by y=\frac{mλD}{a}, m=1, 2, 3, ..., in which D is the distance from the slit to the screen, and a is the slit gap.

What would happen in the same arrangement, but with a double slit? And with multiple slits? And what if, instead of a slit, I had an obstacle, such that the light would (classicaly) go through the sides, but not over the object?

Many thanks
 
Physics news on Phys.org
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top