What is a fColumb? Finding Net Electric potential, still wrong

AI Thread Summary
The discussion centers on calculating the net electric potential at point P due to four particles, with a charge of 5.50 fC and a distance of 3.00 cm. The user initially miscalculated the potential by not converting femtocoulombs (fC) to coulombs, which is essential for accurate results. They corrected their approach by recognizing that the negative charge is 2d away from point P instead of d. After adjusting their calculations, they found a potential of 6.37E-10 V. The prefix "f" in fC stands for femto, indicating a factor of 10^-15.
mr_coffee
Messages
1,613
Reaction score
1
I'm suppose to find the net electric potential at point P due to the four particles, if V = 0 at infinity, q = 5.50 fC, and d = 3.00cm?
THe picture is here: http://www.webassign.net/hrw/hrw7_24-33.gif
I used V = (5.50/.03 + 5.50/.03 - 5.50/.03 - 5.50/(.06));
I noticed that the very end negative charge is 2d away from P not just d. But i only have 2 more chances left to get it right. so i found V = 6.37E-10 V. But I never converted 5.50 fC to just C. So I'm assuming my answer is off slightly, anyone know what fC stands for also, do yuou know if I'm right? Thanks!]
 
Physics news on Phys.org
The potential at a distance r from a point charge is k q/r. The prefix "f" stands for femto, which means 10^{-15}.
 
awesome, thanks guys, it worked great!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top