What is initial slopes of the plot Z versus P ?

AI Thread Summary
The discussion focuses on calculating the initial slopes of compressibility factor Z versus pressure P using the van der Waals constants for hydrogen (H2) and oxygen (O2). The virial expansion is applied, leading to the expression for Z and its derivative with respect to P, which is identified as the initial slope. The calculated slopes for O2 and H2 are -4.07 x 10^-3 bar^-1 and -6.92 x 10^-4 bar^-1, respectively. There is confusion regarding the temperature value to use, as the final answers do not depend on T. The participants seek clarification on which temperature should be used to align with textbook results.
Buffu
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Homework Statement


Use the van der waals constant for ##H_2## and ##O_2## to calculate the initial slopes of the plots of compressibility factor Z versus P.

Homework Equations

The Attempt at a Solution



Using virial expansion for van der waal gas in terms of ##P##

I get ##Z = 1 + \dfrac{1}{RT}\left(b - \dfrac{a}{RT} \right)P + \cdots##

Using first approximation,

Then ##\dfrac{dZ}{dP} = \dfrac{1}{RT}\left(b - \dfrac{a}{RT} \right)##.

What is initial slope in this context ? ##T = 0 ## ?
 
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What you calculated is the initial slope.
 
Chestermiller said:
What you calculated is the initial slope.

But the answer does not involve ##T##.

For ##O_2## it is ##-4.07 \times 10^{-3} bar^{-1}## and for ##H_2## it is ##-6.92 times 10^{-4} bar^{-1}##.

Which value of ##T## should I take ?
 
Buffu said:
But the answer does not involve ##T##.

For ##O_2## it is ##-4.07 \times 10^{-3} bar^{-1}## and for ##H_2## it is ##-6.92 times 10^{-4} bar^{-1}##.

Which value of ##T## should I take ?
I confirm you virial expansion for Z in terms of P and T. Can you please determine the value of T that gives the "book" answers?
 
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