What is the acceleration experienced by the puck?

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The discussion revolves around calculating the acceleration of a hockey puck that comes to a stop due to friction over a distance of 15 meters. Initially, a participant calculated an acceleration of 2.0157 m/s² but was corrected for using the wrong method. After guidance on the correct formula, the participant re-evaluated their calculations and arrived at an acceleration of -1.01 m/s², which was confirmed as accurate by others in the thread. The conversation highlights the importance of using the correct physics equations and understanding the relationship between displacement, initial velocity, and acceleration. Overall, the collaborative effort led to a clearer understanding of the problem.
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I've been attempting the following question:

A 120gram hockey puck sent sliding over ice with an initial speed of 5.5m/s is stopped in 15m by the frictional force on it from the ice.What is the acceleration experienced by the puck?

I'm getting an answer of 2.0157m/s^2.I'm wondering if this is correct or not?
Thanks.
 
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If you assume the acceleration is constant then your answer is incorrect. Perhaps if you show your working we could correct you. Also note that the acceleration should be negative since the puck's velocity is decreasing.
 
i used the formula vf-vi/tf-ti to get that answer
 
petal5 said:
i used the formula vf-vi/tf-ti to get that answer
And how did you calculate the time?
 
i divided 15m by 5.5m.however,i now realize this is wrong as the 5.5m. is INITIAL speed
 
petal5 said:
i divided 15m by 5.5m.however,i now realize this is wrong as the 5.5m. is INITIAL speed
Indeed, so if we assume the acceleration to be uniform how does the displacement, initial and final velocity relate to the acceleration?
 
sorry,i've no idea.
 
would it be this equation:v^2=vo^2+2a(x-xo)
 
  • #10
petal5 said:
would it be this equation:v^2=vo^2+2a(x-xo)
Indeed it would, all that is left to do is some algebraic manipulation and to substitute in your values.
 
  • #11
thanks for all your help.i'm now getting -1.01m/s^2
 
  • #12
petal5 said:
thanks for all your help.i'm now getting -1.01m/s^2
Looks about right to me. My pleasure.
 
  • #13
Thanks so much,you're a great teacher!
 
  • #14
petal5 said:
Thanks so much,you're a great teacher!
Thank you very much :smile: I do my best.
 

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