What Is the Acceleration of a Water Balloon Thrown Downward?

AI Thread Summary
The discussion centers on a physics problem involving the motion of a water balloon thrown downward from a building. Key questions include calculating the balloon's velocity after 2 seconds and after falling 10 meters, as well as determining its acceleration while in the thrower's hand. Participants suggest using kinematic equations to solve for the velocities, emphasizing the need to account for gravitational acceleration. The original poster expresses gratitude for the assistance received and indicates they have resolved the initial problem but have another question pending. Overall, the thread highlights the application of physics equations in projectile motion scenarios.
phys1618
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Please help! projectile motion problem..

Homework Statement



a student throws a water balloon vertically downward fromt he top of a building; the balloon leaves the thrower's hand with a velocity of 10 m/s.
1.what will be its velocity after falling for 2 seconds?
2.what will be its velocity after falling 10 meters?
3.If it moved a distance of 1 meter while int he throwers' hand, find it's accelereation while in his hand.

Homework Equations




d=(vi+vf)t
2

a= (vf-vi)/t

The Attempt at a Solution



I think i can get the answers to 1 and 2. I'm clueless on #3.
thank you for all help! greatly appreciated.
 
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phys1618 said:

Homework Statement



a student throws a water balloon vertically downward fromt he top of a building; the balloon leaves the thrower's hand with a velocity of 10 m/s.
1.what will be its velocity after falling for 2 seconds?
2.what will be its velocity after falling 10 meters?
3.If it moved a distance of 1 meter while int he throwers' hand, find it's accelereation while in his hand.

Homework Equations

d=(vi+vf)t
2

a= (vf-vi)/t

The Attempt at a Solution



I think i can get the answers to 1 and 2. I'm clueless on #3.
thank you for all help! greatly appreciated.

Your second equation will find the velocity after 2 seconds, but your first equation neglects to take into account the acceleration of gravity.

Consider using the relationship that vf2 = vi2 + 2a*x for part 2.

As to your third question, you have the distance, and initial V was at rest and final V is 10m/s so ... use the same equation to figure a.
 


Thank you LowlyPion. I greatly appreciates your fast help. I have the problem solved with no problem. Thanks. however, I do have a another problem just posted. if you can take a look and help me..thank you for your time and help.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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