What is the Angle Between Forces in Equilibrium?

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The discussion revolves around calculating the angle between forces in equilibrium using the Law of Cosines. For the first problem involving forces of 692 N and 423 N, the resultant force is 786 N, and the correct angle calculated is approximately 93.92 degrees. The second problem involves three forces of 980 lbs, 760 lbs, and 1220 lbs, with angles calculated to be around 91.92, 141.49, and 126.6 degrees. Participants express confusion about the Law of Cosines and the relationship between degrees and minutes. Overall, the thread highlights challenges in applying mathematical formulas to solve for angles in force equilibrium scenarios.
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Homework Statement


1. Two Forces of 692 N and 423 N acts at a point. The resultant force is 786 N. Find the angle between the Forces.[SOLVED]

2. Three forces acting at a point are in equilibrium. The forces are 980 lbs, 760 lbs and 1220 lbs. Find the angle between the forces (to the nearest minute)

Homework Equations


The Attempt at a Solution



1. I tried the Law of cosines and I got 91.96 [SOLVED...I had law of cosines wrong, instead of 2abCosX i had a 4]
[Answer: 93.92]2. No idea how to draw it out, or solve. How do you define minutes in relation to degrees? [Answer: 91.92, 141.49 , 126.6]
 
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sorry to tell u..the first one i cannot get the answer u had given... i just get 86.08...far away from your answer...i same with u use the formula...but i finally cannot get the answer..can u tell me...
 
Well, right now I'm in Calculus, Physics C AP next year haha. From last year though, I remember you always have to do the biggest side sooo...7862=6922+4232-2(423)(692)(cosX)
 
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