What is the area of a 7.000 μm thick leaf made of 7.000 oz of gold?

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To find the area of a 7.000 μm thick leaf made from 7.000 oz of gold, the volume must be calculated using the density of gold, which is 19.32 g/cm³. The volume can be expressed as the product of area and thickness, allowing for the calculation of area. For the second part, when the gold is drawn into a cylindrical fiber with a radius of 2.400 μm, the volume can be expressed in terms of the fiber's length and radius. Both calculations require careful unit conversions to ensure accuracy. The discussion emphasizes the importance of understanding the relationships between mass, volume, density, area, and length in these scenarios.
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Gold, which has a mass of 19.32 g for each cubic centimeter of volume, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold with a mass of 7.000 oz, is pressed into a leaf of 7.000 μm thickness, what is the area (in m^2) of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.400 μm, what is the length (in m) of the fiber?

I know its simple but I can't seem to know where to get started
 
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Gold, which has a mass of 19.32 g for each cubic centimeter of volume, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold with a mass of 7.000 oz, is pressed into a leaf of 7.000 μm thickness, what is the area (in m^2) of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.400 μm, what is the length (in m) of the fiber?

I know its simple but I can't seem to know where to get started
 
Use the equation: density = mass/volume

For part a) what is the volume of this leaf in terms of thickness and area... use this along with the above equation to solve for area...

For part b) what is the volume in terms of radius and length... use this with the density equation to solve for height.

Be careful about units.
 
what do you mean by in terms of in terms of thickness and area
 
jjc39 said:
Gold, which has a mass of 19.32 g for each cubic centimeter of volume, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold with a mass of 7.000 oz, is pressed into a leaf of 7.000 μm thickness, what is the area (in m^2) of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.400 μm, what is the length (in m) of the fiber?

I know its simple but I can't seem to know where to get started

mass is given, density is given. You know the volume then. This volume is fixed. So, get your area (first case) and length (2nd case) accordingly.
 
jjc39 said:
what do you mean by in terms of in terms of thickness and area

Volume = area * thickness
 

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