Calculating Average Force in a Car Collision

AI Thread Summary
To calculate the average force during a car collision, a 1200 kg car traveling at 14 m/s rebounds at 3 m/s over a duration of 0.10 seconds. The change in velocity is calculated as 17 m/s, using the formula 14 m/s - (-3 m/s). The force is then computed with the equation F = mass * change in velocity / change in time, resulting in an initial calculation of 204,000 N. However, a signage error in the velocity change was noted, and the correct unit for force should be included. The discussion emphasizes the importance of accurate sign conventions and units in physics calculations.
ScullyX51
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Homework Statement


A 1200 kg car drives headlong into a brick wall at 14 m/s and rebound at 3 m/s. The collision lasts for .10 seconds. What is the average force on the car during the collision?


Homework Equations


F=ma
f*change in time= mass * change in velocity
f= mass*change in velocity / change in time


The Attempt at a Solution


I got the change in velocity to be 17 m/s. I did 14 m/s - (-3m/s) = 17 (I put the 3 as negative since it it rebounding it is going in the negative x direction.
f= 1200(17)/ .1 = 204,000. this is wrong..where am I messing up?
 
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ScullyX51 said:

Homework Statement


A 1200 kg car drives headlong into a brick wall at 14 m/s and rebound at 3 m/s. The collision lasts for .10 seconds. What is the average force on the car during the collision?


Homework Equations


F=ma
f*change in time= mass * change in velocity
f= mass*change in velocity / change in time


The Attempt at a Solution


I got the change in velocity to be 17 m/s. I did 14 m/s - (-3m/s) = 17 (I put the 3 as negative since it it rebounding it is going in the negative x direction.
f= 1200(17)/ .1 = 204,000. this is wrong..where am I messing up?
The change in velocity is (final v - initial v). You may have a signage error. And don't forget the force unit.
 
Looks good to me, except for you not including the correct unit for force.
 
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