What Is the Cathode Metal in This Photoelectric Experiment?

  • Thread starter Thread starter btbam91
  • Start date Start date
  • Tags Tags
    Electric Photo
AI Thread Summary
In the discussed photoelectric experiment, the stopping potential at 400 nm is 25.7% of that at 300 nm, indicating a relationship between the two wavelengths. To determine the cathode metal, one must first calculate the stopping potential for 300 nm using the equation V(stop) = Kmax/e, where Kmax is derived from Kmax = hf - Eo (work function). The same metal is used for both wavelengths, confirming that the stopping potentials will differ as expected due to the wavelength dependency. The discussion suggests setting up two equations to solve for the unknowns, specifically the stopping potentials and the work function. Understanding these relationships is crucial to identifying the cathode metal in the experiment.
btbam91
Messages
91
Reaction score
0
In a photoelectric-effect experiment, the stopping potential at a wavelength of 400 nm
is 25.7% of the stopping potential at a wavelength of 300 nm. Of what metal is the
cathode made?

So I need to find the stopping potential of the metal with a wave length of 400 nm, but first I need to find the stopping potential of the metal with a wave length of 300 nm.


Using:

V(stop)=Kmax/e

Kmax=hf-Eo(work function)

How do I find the work function for the 300 nm?


Thanks.
 
Physics news on Phys.org
I believe that the problem states that it is the same metal for both cases. That is, the same cathode has 400 nm light, then 300 nm light shone on it, and the result was that the stopping potential was less for the longer wavelength light (which is expected), and in fact was only 25.7% of the stopping potential for the shorter wavelength light.

Sounds like a case of setting up two equations in two unknowns and solving. Write expressions for both stopping potentials, then use the given information about their numerical relationship.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

Similar threads

Back
Top