What is the charge on the left-hand plate of C4?

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The discussion centers on determining the charge on the left-hand plate of capacitor C4, given that the left-hand plate of capacitor C1 has a charge of +24 μC. The key concept is that the charges on capacitor plates must be equal and opposite due to conservation of charge. Since the left plate of C4 is adjacent to the negative terminal of the battery, it is inferred that its charge would be negative. The conclusion drawn is that the charge on the left-hand plate of C4 is -24 μC. Understanding these principles is crucial for solving similar capacitor problems in circuits.
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The capacitors in the circuit below are all identical. The EMF of the battery is unknown.
http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys212/oldexams/exam1/sp08/fig24.gif

If the charge on the left-hand plate of C1 is +24 μC, what is the charge on the left-hand plate of C4?

(a) Q4 = -24 μC
(b) Q4 = -12 μC
(c) Q4 = 0
(d) Q4 = +12 μC
(e) Q4 = +24 μC

What's the concept behind this? Is it -24 uC because the left plate of C4 is next to the negative terminal of the battery?
 
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Only two left plates are connected directly to E. According to conservation of charges the charges on two plates must be equal and opposite.
 

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