What is the correct method of finding the direction of a Vector

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Homework Help Overview

The discussion revolves around the methods for determining the direction of a vector, specifically in the context of two examples involving vector AB and the resultant of vectors A and B. Participants explore the angles formed with different axes and the implications of these choices on the direction of the vectors.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question why the angle between vector AB and the y-axis is considered instead of the x-axis. There is also a discussion about the resultant vector's direction and the angles used to define it.

Discussion Status

Some participants have provided insights suggesting that the choice of axis for measuring angles is arbitrary, as long as it is clearly stated. There is an acknowledgment that both methods of determining direction can yield valid results, but no consensus has been reached on a singular "correct" method.

Contextual Notes

Participants note that the direction of a vector is relative to the origin and reference frame, which may vary based on the context of the problem. There is an emphasis on the importance of specifying the axis used for angle measurement.

Aladin
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How the direction of a vector is found ?
In figure "a" we want to find the direction of the vector AB.In order to find the direction of vector AB,why we considered the angle between AB and y-axis.Why we did not considered this angle between AB and x-axis.
---------------------------------------------------------------------
On the other hand the figure ''b".
Also in second example we want to find the direction of the resultant vector of A and B.While A=3cm and B=4cm.
Its resultant will be A+B=5cm.
Now we find the direction of A+B.
I see in my book that the angle is found between resultant vector (A+B) and A i.e (x-axis) the answer is 53 degree.that is correct.
but answer of the first example is also correct.
................
1) Please tell me what is the correct mathod of finding the direction of a vector.
 

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Aladin said:
How the direction of a vector is found ?
In figure "a" we want to find the direction of the vector AB.In order to find the direction of vector AB,why we considered the angle between AB and y-axis.Why we did not considered this angle between AB and x-axis.
---------------------------------------------------------------------
On the other hand the figure ''b".
Also in second example we want to find the direction of the resultant vector of A and B.While A=3cm and B=4cm.
Its resultant will be A+B=5cm.
Now we find the direction of A+B.
I see in my book that the angle is found between resultant vector (A+B) and A i.e (x-axis) the answer is 53 degree.that is correct.
but answer of the first example is also correct.
................
1) Please tell me what is the correct mathod of finding the direction of a vector.
The direction of a vector is relative to the origin and the reference frame. The choice of the origin and reference frame is arbitrary. So long as you specify which axis it is relative to, there is no problem.

AM
 
Aladin said:
In order to find the direction of vector AB,why we considered the angle between AB and y-axis.Why we did not considered this angle between AB and x-axis.
Just to add to Andrew's explanation: It doesn't matter which axis you use to specify the direction of a vector—either one will do. And if you know the angle made with the y-axis, you should be able to figure out the angle made with the x-axis.
 
Please give me another example to explain the vector direction method.
 
It is irrelevant which from which axis you chose to take the angle, so long as you state this in your answer. For example say you have a 2D vector [itex]l = 3i + 4j[/itex] where i and j are unit vectors in the positive x and y direction respectively. Now, the magnitude of the vector would of course be;

[tex]\left| l \right| = \sqrt{3^2 + 4^2} = 5[/tex]

Now, it is up to use from which axis (x or y) we wish to take the angle. You may at this point wish to draw yourself a diagram. First let's take the angle anti-clockwise from the x axis;

[tex]\theta = \tan^{-1} \left( \frac{4}{3} \right) \approx 53.1^{o}[/tex]

Therefore, the vector would have a magnitude of 5 acting 53.1o anti-clockwise from the x axis.

Alternatively, we could take the angle clockwise from the y axis, in which case the angle would be;

[tex]\theta = 90 - \tan^{-1} \left( \frac{4}{3} \right) \approx 36.9^{o}[/tex]

And therefore, our vector would still have a magnitude of 5 and is directed 36.9o clockwise from the y axis.
 
Thank you Hootenanny .This example is proved helpful for me.
 

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