What is the distance of the image?

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The discussion focuses on calculating the image distance from a converging mirror using the formula 1/object-mirror distance + 1/image-mirror distance = 1/mirror's focal length. The object is 19.5 cm from the mirror with a focal length of 5.5 cm, resulting in an image distance of approximately 7.66 cm. This distance indicates that the image is real and inverted since it is farther than the focal point. Additionally, the magnification formula, Di/Do, is mentioned to determine the size and orientation of the image. The conversation confirms the calculations and explores the characteristics of images formed when objects are positioned closer to the focal point.
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An object is located 19.5 cm from a converging mirror with a focal length of 5.5 cm. What is the distance of the image? Is it real or virtual? Is it smaller or larger than the object? Is it upright or inverted?
This is the equation I need to use for the problem
1/object-mirror distance + 1/image-mirror distance= 1/mirror"s focal lenth to solve for image-mirror distance
This is how I solved for the problem
1/image-mirror distance = 1/5.5 - 1/19.5 = .1305361305 then I have to find the reciprocal which is 1/.1305361305 = 7.660714288 or 7.66cm
Have I solved this correctly?
 
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It's farther than the focal point, which immediately tells you that it's real and inverted.

but i believe you have solved correctly
remember, magnification is Di/Do
 
Okay, then when it's closer than the focal point, does that mean that it's virtual and upright?
 

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