What Is the Effective Resistance of Headlights in a Car Battery Circuit?

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To calculate the effective resistance of the headlights in a car battery circuit, consider the battery's internal resistance and the voltage drop when the headlights are on. The battery has a source voltage of 12.00 V and an internal resistance of 0.015 Ω, resulting in a voltage drop to 11.75 V when the headlights are activated. This indicates a voltage drop of 0.25 V across the internal resistance, allowing for the calculation of current drawn by the headlights. The effective resistance of the headlights can be determined using Ohm's law, where effective resistance is equivalent to normal resistance in this context. Understanding these principles will enable accurate calculations of the circuit's effective resistance.
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I can't seem to get this one, I just don't know how to calculate the effective resistance, what is the difference between effective resistance and normal resistance??

Here is the question:


A car battery has a source voltage of 12.00 V and an internal resistance of
0.015 Ω. When the headlights are turned on (while the engine is not running)
the output voltage of the battery drops to 11.75 V. The effective resistance of
the headlights is nearest to:



If someone could just give me a formula or some hints...that would be great!
 
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dblanche said:
I can't seem to get this one, I just don't know how to calculate the effective resistance, what is the difference between effective resistance and normal resistance??

Here is the question:


A car battery has a source voltage of 12.00 V and an internal resistance of
0.015 Ω. When the headlights are turned on (while the engine is not running)
the output voltage of the battery drops to 11.75 V. The effective resistance of
the headlights is nearest to:
Think of the battery as a pure source of 12V in series with a .015 Ω resistor. At the current drawn when the headlight is connected, the voltage drop across the resistor is .25V. Work out that current and determine what the resistance of the headlight is.

The effective resistance is the same as the normal resistance.

AM
 
hello,may i know what the answer?
 
chai940610 said:
hello,may i know what the answer?
Welcome to PF. The short answer is NO. You have to try to work it out first.

AM
 
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