What is the Effective Spring Constant for a System in Series?

AI Thread Summary
The discussion focuses on calculating the effective spring constant for two springs in series, where a mass hangs from the lower spring. To find the total extension distance and the effective spring constant, participants emphasize using Hooke's Law and the relationship for springs in series, which states that the effective spring constant k is given by 1/k = 1/k1 + 1/k2. It is noted that the resulting effective spring constant will be less than either k1 or k2, indicating that the combined system will oscillate more than the individual springs. Participants also highlight the importance of ensuring the units are consistent in the equations used. The conversation concludes with a correction regarding the proper formulation of the equations.
student 1
Messages
76
Reaction score
0

Homework Statement


A light spring with spring constant k1 hangs from a second light spring, which has spring constant K2. An object of mass m hangs at rest from the lower end of the second spring. A. Find the total extension distance of the pair of springs. B. Find the effective spring constant of the pair of springs as a system. We describe these springs as in a series.


Homework Equations

Hooke's Law K=mg/d



The Attempt at a Solution

Where should I start? Would just combine the k's I do not know where to go with this problem?
 
Physics news on Phys.org
You should draw out the force diagram and get the force equations from them. You should get 2 equations and they are all you need
 
I'd actually do part B first. They are asking you for k, the spring constant for both springs. If the springs are in series, as a rule, k = \frac{1}{k1} + \frac{1}{k2}. Notice that the resulting k value will be less then both k1 and k2, meaning that the resultant spring will oscillate more then k1 or k2.

Now that you know the k value, you can plug that into hooke's law to get the distance
 
So my D=(mg)(K1K2)/(K1+K2)
 
Hi student 1,

student 1 said:
So my D=(mg)(K1K2)/(K1+K2)

No, that's not quite right. Notice that it does not have the right units (meters on the left, N^2/m on the right).
 
blaaaah i forgot a very important part in the equation i gave you: \frac{1}{k} = \frac{1}{k1} +\frac{1}{k2}. My apologies, student1
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top