The discussion revolves around calculating the elastic modulus of a wire based on its diameter, the force applied, and the resulting stretch. The problem involves understanding the relationship between force, area, length, and change in length.
Participants are actively engaging with the problem, with some offering corrections to the original poster's calculations. There is a recognition of potential errors in the area calculation and the ratio of change in length to original length, but no consensus has been reached on the correct approach yet.
There is a mention of specific values for diameter and force, as well as the percentage stretch of the wire, which are critical to the calculations but may not have been applied correctly by the original poster.
That should be (F/A)/(ΔL/L).joseg707 said:Homework Equations
Elastic Modulus=F/A/L/[tex]\Delta[/tex]L
Area = pi*r². Looks like you have an extra factor of two in there. And ΔL/L = 0.002.joseg707 said:6.28N/(2[tex]\pi[/tex]1x10-8/.02=5x109N/m2