What is the electric field at the point x = 3.5 m, y = 2.0 m?

AI Thread Summary
The electric potential is defined as V = axy, with a = 1.7 V/m². To find the electric field at the point (3.5 m, 2.0 m), the calculation yields V = 11.9 V, but clarification on unit vector notation is needed. For part (b), the initial acceleration of a particle with mass 1.67 × 10^-27 kg and charge 1.6 × 10^-19 C can be determined using F = ma. The discussion emphasizes the relationship between electric potential and electric field, as well as the application of Newton's second law for acceleration. Understanding these concepts is crucial for solving the problem accurately.
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1. Homework Statement [/b]

The electric potential in a region of space is given by V = axy where a = 1.7 V/m2.

(a) What is the electric field at the point x = 3.5 m, y = 2.0 m? Give your answer in unit
vector notation.

(b) If a particle of mass m = 1.67 × 10 −27 kg and charge q = +1.6 × 10 −19 C is released from
this point, what is the magnitude of its initial acceleration?

Homework Equations



V=axy

The Attempt at a Solution


(a)V=(1.7)(3.5)(2)
11.9
This seems to simple is this correct. Also do not understand unit vector notation.
(b) unsure of the equation to use
 
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Bri15 said:
1. Homework Statement [/b]

The electric potential in a region of space is given by V = axy where a = 1.7 V/m2.

(a) What is the electric field at the point x = 3.5 m, y = 2.0 m? Give your answer in unit
vector notation.

(b) If a particle of mass m = 1.67 × 10 −27 kg and charge q = +1.6 × 10 −19 C is released from
this point, what is the magnitude of its initial acceleration?

Homework Equations



V=axy

The Attempt at a Solution


(a)V=(1.7)(3.5)(2)
11.9
This seems to simple is this correct. Also do not understand unit vector notation.
(b) unsure of the equation to use

(a) What's the formula for the electric field, given the potential?
(b) F = ma
 
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