What is the Electric Field in a Ball with a Positive Charge at R/2?

AI Thread Summary
The discussion revolves around calculating the electric field at a distance of R/2 from a uniformly charged ball with a positive charge Q. The user attempted to apply the electric field equations but arrived at an incorrect answer, leading to confusion about the problem's wording regarding the location of the point charge. There is a suggestion to clarify the problem statement to ensure accurate interpretation. The correct answer involves a specific formula, K*(1/18)*(Q/r^2), indicating a misunderstanding in the application of the electric field equations. Clear communication of problem details is essential for accurate problem-solving in physics.
dannee
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Homework Statement



Positive charge Q uniformly distributed in a ball with radius R, which is located at the beginning of X axis. Positive point charge Q is located on the X axis on R=2. what is the size of the electric field in R/2?


Homework Equations





The Attempt at a Solution



i've tried to use the equations of electric field, K*(Q/r^2), once put the distance of charge Q with R=3/2, adding it to the electric field of the ball on the point, which is K*(Q/a^3), as a=0.5R. but the correct answer is K*(1/18)*(Q/r^2). where do i go wrong?
 
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Are you sure that the problem says on the axis at R=2, not X=2R? The wording of the problem you put up is really bad, maybe you could post exactly what the problem you were given says.
 

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