What is the Electric Field of a Uniformly Charged Disk at Different Z Positions?

AI Thread Summary
The discussion centers on calculating the electric field (Ez) of a uniformly charged disk at a specific position along the z-axis. The formula used for Ez is derived from the general equation for electric fields, but the initial attempt led to an incorrect result. A participant suggests that the formula applied is meant for rings rather than disks, indicating a need for a different approach. A link to a relevant resource is provided to guide the correct calculation. The conversation highlights the importance of using the appropriate equations for different geometrical charge distributions.
fallen186
Messages
41
Reaction score
0

Homework Statement


A nonconducting disk of radius a lies in the z = 0 plane with its center at the origin. The disk is uniformly charged and has a total charge Q. Find Ez on the z axis at the following positions. (Assume that these distances are exact.)

Z = a
[__________]Q / (a2εo) - This is the format the answer should be in.

Homework Equations



Ez = \frac{kQz}{(z^2+a^2)^{3/2}}

k = 1/(2pi*εo)

The Attempt at a Solution


1. Ez = \frac{kQz}{(z^2+a^2)^{3/2}}

I filled in 'z' and 'k'

2. Ez = \frac{Qa}{(a^2+a^2)^{3/2}*2\pi*\epsilon}

3. Ez = \frac{Qa}{(2a^2)^{3/2}*2\pi*\epsilon}

4. Ez = \frac{Qa}{8a^{3}*2\pi*\epsilon}

5. Ez = \frac{Q}{(16\pi*a^{2}*\epsilon}

6. 1/16\pi

7. [_.1963495408_]Q / (a2εo) * Its wrong and I don't know what I did wrong. Please help
 
Physics news on Phys.org
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top