What is the electric field problem involving two point charges?

AI Thread Summary
The discussion revolves around solving an electric field problem involving two point charges, q1 and q2, placed on the x-axis. The objective is to find the x-coordinate on the positive x-axis where the electric field is zero, indicating no net force on a test charge. The solution involves equating the magnitudes of the forces exerted by the two charges on the test charge, leading to the equation k*q3*q1/(x-3)^2 = k*q3*q2/(x+1)^2. After solving, the correct position for the test charge is determined to be at 7 cm from the origin, as it must be beyond the location of q2 to ensure the forces act in opposite directions. A diagram is suggested to clarify the distances involved in the calculations.
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Electric Field Problem -Easy please help

Homework Statement



Two point charges, q1 = 4.0×10-6 C and q2 = -1.0×10-6 C, are located on the x-axis at x1 = -1.0 cm and x2 = 3.0 cm.

Determine the x coordinate of a point on the positive x-axis where the electric field is zero; i.e., a test charge placed at this point would experience no force.

Homework Equations



kq/(r^2)

The Attempt at a Solution



Don't know, please help, I would like to know how to solve this.
 
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I am not good in electric field. So, i will ... the problem with electrical force.
Let this test charge is +x cm from the origin.
Experience no force: The forces that act on this test charge by charge 1 and 2 must be the same in magnitude but in opposite directions. one will repel the test charge in one direction, the other will attract in the opposite direction.
Considering only he magnitude of the two forces:
k*q3*q1/(x-3)^2 = k*q3*q2/(x+1)^2 [remember to take the magnitude only especially the charge]
solving for x, you suppose to get 7 cm and 5/3 cm .
The answer will be 7 cm. since this test charge cannot be less than +3 cm from the origin, otherwise zero net force will not be possible since the the two forces acting on test charge are in the same direction.
 
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Yes, 7cm is the right answer, thank you Leong. I understand that the forces are equal yet opposite, but where did you get the equation
k*q3*q1/(x-3)^2 = k*q3*q2/(x+1)^2 from? What I really mean is where does (x-3) and (x+1) come from?
 
x-3 is the distance between q3 and q2. x + 1 is the distance between q3 and q1. draw the diagram, put the test charge to the left of q2, thenit will be clearer.
 
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