Archived What is the entropy of mixing for a system of two monatomic ideal gases?

AI Thread Summary
The discussion focuses on calculating the entropy of mixing for two monatomic ideal gases, A and B, using the formula ΔS = -Nk[xlnx + (1-x)ln(1-x)], where N is the total number of molecules and x is the fraction of species B. The user initially struggled with algebra but believes they have resolved the issue, confirming the use of the ideal gas law PV = nkT. They express uncertainty about what changes occur between the initial and final states in terms of entropy. The conversation highlights the need to understand how the volume changes when mixing gases at constant pressure. The final expression should align with the text's formula when x equals 1/2.
Thadis
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I think I actually have solved it. I was right with the PV=nkT, I believe I previously messed up with the algebra.

Homework Statement



Using the same meathod as in the text, calculate the entropy of mixing for a system of two monatomic ideal gases, A and B, whose relative proportion is arbitrary. Let N be the total number of molecules and let x be the fraction of these that are species B. You should find that

ΔS=-Nk[xlnx+(1-x)ln(1-x)]

Check that this expression reduces to the one given in the text when x= 1/2.

Homework Equations


That S=Nk[ln(V(a/3n)^(3/2))+3/2] where a is just a whole bunch of stuff that I believe is irrelevant to the problem.

PV=nkT might be useful

also the fact that ln(x/y)=ln(x)-ln(y)

The Attempt at a Solution



I know that the change of entropy will just be S_final-S_original but I do not know what really changes between the final and the original situations. Do I have to use the Ideal Gas law find out how big the volume would be?
 
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This is a constant single pressure process; the original statement is about as obfuscated as is possible. "n" volumes of pure gases are mixed by volume fraction.
 
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