What is the equation for calculating tension in an elevator rope?

AI Thread Summary
To calculate the tension in an elevator rope, the combined mass of the elevator and load is 1500 kg. The elevator decelerates from 11 m/s to rest over a distance of 43 m, requiring the calculation of time and acceleration. The initial calculation for time was determined to be approximately 0.78 seconds, leading to an acceleration of 14.1 m/s². The force was incorrectly calculated as 35,850 N, indicating a need for reevaluation of the calculations. Accurate tension calculation is crucial for understanding the forces acting on the elevator system.
B-80
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An elevator and its load have a combined mass of 1500 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 11 m/s, is brought to rest with constant acceleration in a distance of 43 m.

First I found the time it to to decelerate
D=(V+Vo)/2 T
gave me a value of .78seconds
plugged it into V=Vo+at
a=14.1m/s^2

F=ma
so the force is 1500Kg * (9.8+14.1) which is 35850
thats wrong, thanks in advance
 
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B-80 said:
First I found the time it to to decelerate
D=(V+Vo)/2 T
gave me a value of .78seconds
Redo this calculation.
 
thanks, stupid decimal.
 
How did you figure out the time?
 
SolidTwinz said:
How did you figure out the time?
Read the first post. (Distance = average speed X time)

This thread is 4 years old.
 

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