What is the equation for the given curve in polar coordinates?

AI Thread Summary
The discussion focuses on converting the parametric equations x = e^Kcos(k) and y = e^Ksin(k) into polar coordinates. The key transformation results in the equation r = e^k, where r represents the radial distance and k is the angle. The participant clarifies that the relationship between x, y, and r leads to the conclusion that r^2 = e^(2k). The final answer, r = e^k, accurately describes the curve in polar coordinates, maintaining consistency with the original parametric forms. This conversion effectively captures the essence of the curve defined by the initial equations.
SPhy
Messages
24
Reaction score
0

Homework Statement



x = eKcos(k)
y=eKsin(k)

-∞ < K < ∞

Find an equation in polar coordinates for the above curve


The Attempt at a Solution



I am not fully clear as to what the question is asking.

If its asking for (r,k), where K is normally a theta value then it would be (e^k,k)

other than that,

x^2+y^2=e^2k

r^2 = e^2k

r = √e^2k = e^k

---

Any help or suggestions would be appreciated!
 
Physics news on Phys.org
r = ek is the answer you're looking for. It's an equation in polar coordinates and spans the same curve as your original parametric equations.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top