What is the estimated path length traveled by a deuteron in a cyclotron?

AI Thread Summary
The discussion focuses on estimating the total path length traveled by a deuteron in a cyclotron with a radius of 53 cm and an operating frequency of 12 MHz, where the accelerating potential is 80 kV. The calculations involve determining the kinetic energy (KE) of the deuteron upon exiting the cyclotron and the energy gained per crossing of the dees. The initial attempt estimated the total path length based on the number of revolutions, resulting in an estimated distance of 346 m, while the expected answer is 240 m. Participants suggest refining the approach by calculating the trajectory radius after multiple revolutions and utilizing programming tools for more accurate results. The discussion highlights the complexities of calculating particle paths in cyclotrons and the need for precise methods.
gmark
Messages
13
Reaction score
0

Homework Statement


Estimate the total path length traveled by a deuteron in a cyclotron of radius 53 cm and operating frequency 12 MHz during the entire acceleration process. Accelerating potential between dees is 80 kV.

mass m = 3.2e-27 kg
charge q = 1.6e-19 C
radius r = 0.53 m
frequency f = 12e6 /s
potential V = 80e3 V

Homework Equations



(1) kinetic energy KE = .5*m*v^2

Consider a charged particle of mass m, charge q, velocity v perpendicular to magnetic field B. The particle will travel in a circle of radius r with frequency f:

(2) r = (m*v)/(q*B)

(3) f = (q*B)/(2*pi*m)

(4) V = J/C

The Attempt at a Solution



My plan is to calculate the KE the particle has on leaving the machine (r = .53m). This total KE results from N crossing of the dees. So divide the final KE by the KE per crossing to get N. The total number of revolutions is half of N. Estimate the total path length by multiplying N/2 by the outer circumference of the machine, 2*pi*r.

1. Final KE

rearrange (2) above: v = (r*q*B)/m

substitute for v in (1):
(5) KE = (m/2)*(r*q*B/m)^2

rearrange (2) B = (2*pi*m*f)/q

substitute for B in (5) and simplify: KE = 2*m*(r*pi*f)^2

Using values given above, KE = 2.67e-12 J (r = .53m).

2. KE per crossing

rearrange (4) J = V*C

Using values given (V=80e3, C=1.6e-19)
KE = 1.28e-14 J

Dividing total KE by per-crossing KE gives 208 crossings, 104 revolutions.

3. Estimated distance is 2*pi*r*104 (r=.53m) = 346 m.

Given answer is 240 m.


??
 
Physics news on Phys.org
Hi,
gmark said:
Estimate the total path length by multiplying N/2 by the outer circumference of the machine, 2*pi*r.
Particle doesn't start at the outer rim but very close to the center
 
Thanks for your reply. Unfortunately I don't know how to proceed. All I can think of is silly: take the derivative of final KE (step 1 above) wrt the radius, and integrate from r=0 to r=0.53. This accomplishes nothing, of course, and results in the same wrong answer I got before.
 
Calculate the trajectory radius after 1, 2, 3, etc revolution (= 2, 4, 6, ... acceleration steps)
 
Thanks. That works. Yay for Python and brute force.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top