What Is the Final Position of a Vector Rotated Clockwise by 110°?

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Vector A, initially pointing east, is rotated clockwise by 110°, resulting in a final position that can be described as 20 degrees west of south. The discussion clarifies the difference between stating the angle as "70° east of south" and "70° south of east," emphasizing the importance of the reference direction. The vector ultimately resides in the fourth quadrant, confirming its orientation. A diagram is suggested for better understanding of the rotation. The correct final position is clearly identified as 20 degrees west of south.
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Homework Statement



Vector A is initially pointing eastward. This vector is rotated clockwise by an angle of 110°. Which of the following statements is correct regarding the final position of vector A ?



Homework Equations



none

The Attempt at a Solution


I narrowed down my choices to 2:

Vector A is initially pointing eastward. This vector is rotated clockwise by an angle of 110°. Which of the following statements is correct regarding the final position of vector A ?

It is pointing 70° east of south.
or
It is pointing 70° south of east.
What's the difference?

The vector ends up in 4th quadrant with a 70 degree angle but i can choose which choice it is.
 
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nvm i understand:

Answer equals 20 degrees west of south
 
Torshi said:
It is pointing 70° east of south.
or
It is pointing 70° south of east.
What's the difference?
For 'east of south' you start off pointing south, then go east. Which way is east?
For 'south of east' you start off pointing east, then go south.

Compare these directions with the given vector. (Actually draw a diagram, indicate east, then rotate by 110 degrees.)

The vector ends up in 4th quadrant with a 70 degree angle but i can choose which choice it is.
You might want to reconsider the other choices.
 
Torshi said:
Answer equals 20 degrees west of south
There you go.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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