What is the Force Between Two Protons 1.0m Apart?

AI Thread Summary
To find the force between two protons 1.0m apart, the relevant equation is Coulomb's law, which states that the force can be calculated using the formula F = k * (q1 * q2) / r². Here, k is the Coulomb's constant (approximately 9E+9 N m²/C²), and both protons have a charge of 1.602E-19C. The calculation involves substituting these values into the formula, resulting in F = (9E+9 * (1.602E-19)²) / (1.0)². After performing the math, the force can be determined. The discussion emphasizes the importance of correctly applying the formula and performing the calculations.
ajd
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Homework Statement


two protons are 1.0m apart. find the force acting on them.
q1= 1.602E-19C
q2= 1.602E-19c

Homework Equations



i just don't get how to work it out

The Attempt at a Solution


ive got this far up to now [(9E+9)(1.602E-19)(1.602E-19)]/(1.0)². don't know where to go from here
 
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ajd said:

Homework Statement


two protons are 1.0m apart. find the force acting on them.
q1= 1.602E-19C
q2= 1.602E-19c

Homework Equations



i just don't get how to work it out

The Attempt at a Solution


ive got this far up to now [(9E+9)(1.602E-19)(1.602E-19)]/(1.0)². don't know where to go from here

Just do the math.
 
ok i think i got it now
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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